Physics formula

specific heat is one of the necessary material constants in physics, basic principles, formulas and applications relating to the use of specific heat in much more detail later learned, this article gives a brief description, along with examples of solid matter of the specific heat.Specific heat is another physical property of matter. All matter has a temperature associated with it. The temperature of matter is a direct measure of the motion of the molecules: The greater the motion the higher the temperature:

Concept
The amount of heat energy (q) gained or lost by a substance is equal to the mass of the substance (m) multiplied by its specific heat capacity (Cg) multiplied by the change in temperature (final temperature - initial temperature)







Specific Heat Capacity (C_g) of a substance is the amount of heat required to raise the temperature of 1g of the substance by 1^oC (or by 1 K)

Specific Heat  Capacity Common Material

Material	Specific Heat Capacity - cp -
	(Btu/lbmoF) (kcal/kgoC)	(kJ/kg K)
Aluminum, 0oC	0.21	0.87
Antimony	0.05	0.21
Apatite	0.2	0.84
Asbestos cement board	0.2	0.84
Asbestos mill board	0.2	0.84
Ashes	0.2	0.84
Asphalt	0.22	0.92
Augite	0.19	0.8
Bakelite. wood filler	0.33	1.38
Bakelite. asbestos filler	0.38	1.59
Barite	0.11	0.46
Barium	0.07	0.29
Basalt rock	0.2	0.84
Beeswax	0.82	3.4
Beryl	0.2	0.84
Bismuth	0.03	0.13
Bone	0.11	0.44
Borax	0.24	1
Boron	0.31	1.3
Brass	0.09	0.38
Brick, common	0.22	0.9
Brick, hard	0.24	1
Cadmium	0.06	0.25
Calcite 32 - 100F	0.19	0.8
Calcite 32 - 212F	0.2	0.84
Calcium	0.15	0.63
Carbon, Diamond	0.12	0.52
Carbon, Graphite	0.17	0.71
Carborundum	0.16	0.67
Cassiterite	0.09	0.38
Cement dry	0.37	1.55
Cement powder	0.2	0.84
Charcoal	0.24	1
Chalk	0.22	0.9
Chalcopyrite	0.13	0.54
Charcoal, wood	0.24	1
Chromium	0.12	0.5
Clay	0.22	0.92
Coal, anthracite	0.3	1.26
Coal, bituminous	0.33	1.38
Cobalt	0.11	0.46
Coke	0.2	0.85
Concrete, stone	0.18	0.75
Concrete, light	0.23	0.96
Copper	0.09	0.39
Corkboard	0.45	1.9
Corundum	0.1	0.42
Diamond	0.15	0.63
Dolomite rock	0.22	0.92
Earth, dry	0.3	1.26
Fiberboard, light	0.6	2.5
Fiber hardboard	0.5	2.1
Firebrick	0.25	1.05
Fluorite	0.22	0.92
Fluorspar	0.21	0.88
Galena	0.05	0.21
Garnet	0.18	0.75
Glass	0.2	0.84
Glass, crystal	0.12	0.5
Glass, plate	0.12	0.5
Glass, Pyrex	0.18	0.75
Glass, window	0.2	0.84
Glass, wool	0.16	0.67
Gold	0.03	0.13
Granite	0.19	0.79
Graphite	0.17	0.71
Gypsum	0.26	1.09
Hairfelt	0.5	2.1
Hermatite	0.16	0.67
Hornblende	0.2	0.84
Hypersthene	0.19	0.8
Ice-112oF	0.35	1.47
Ice-40oF	0.43	1.8
Ice-4oF	0.47	1.97
Ice32oF (0oC)	0.49	2.09
India rubber min	0.27	1.13
India rubber max	0.98	4.1
Iridium	0.03	0.13
Iron, 20oC	0.11	0.46
Labradorite	0.19	0.8
Lava	0.2	0.84
Limestone	0.2	0.84
Lead	0.03	0.13
Leather, dry	0.36	1.5
Lithium	0.86	3.58
Magnetite	0.16	0.67
Malachite	0.18	0.75
Manganese	0.11	0.46
Magnesia (85%)	0.2	0.84
Marble, mica	0.21	0.88
Mercury	0.03	0.14
Mica	0.12	0.5
Mineral wool blanket	0.2	0.84
Oliglocose	0.21	0.88
Orthoclose	0.19	0.8
Paper	0.33	1.4
Paraffin wax	0.7	2.9
Peat	0.45	1.88
Plaster, light	0.24	1
Plaster, sand	0.22	0.9
Plastics, foam	0.3	1.3
Plastics, solid	0.4	1.67
Platinum, 0oC	0.032	0.13
Porcelain	0.26	1.07
Potassium	0.13	0.54
Pyrex glass	0.2	0.84
Pyrolusite	0.16	0.67
Pyroxylin plastics	0.36	1.51
Quartz mineral 55 - 212oF	0.19	0.8
Quartz mineral 32oF (0oC)	0.17	0.71
Rock salt	0.22	0.92
Rubber	0.48	2.01
Salt	0.21	0.88
Sand	0.19	0.8
Sandstone	0.22	0.92
Sawdust	0.21	0.9
Serpentine	0.26	1.09
Silica aerogel	0.2	0.84
Silk	0.33	1.38
Silver, 20oC	0.056	0.23
Sodium	0.3	1.26
Soil, dry	0.19	0.80
Soil, wet	0.35	1.48
Stone	0.2	0.84
Stoneware	0.19	0.8
Sulphur	0.17	0.71
Tar	0.35	1.47
Tellurium	0.05	0.21
Tile hollow	0.15	0.63
Topaz	0.21	0.88
Tungsten	0.04	0.17
Vanadium	0.12	0.5
Vermiculite	0.2	0.84
Vulcanite	0.33	1.38
Wood, balsa	0.7	2.9
Wood, oak	0.48	2
Wood, white pine	0.6	2.5
Wool, loose	0.3	1.26
Wool, felt	0.33	1.38

Example
1. How much energy does it take to raise the temperature of 50 g of copper by 10^oC?

2. Calculate the amount of heat needed to increase the temperature of 250g of water from 20^oC to 56^oC.
q = m x C_g x (T_f - T_i)
m = 250g
C_g = 4.18 J ^oC^-1 g^-1 (from table above)
T_f = 56^oC
T_i = 20^oC
q = 250 x 4.18 x (56 - 20)
q = 250 x 4.18 x 36
q = 37 620 J = 38 kJ

Reference
http://www.ausetute.com.au/
http://www.tutor4physics.com/formulas.htm
http://www.xs4all.nl/~johanw/physics.pdf
 http://www.engineeringtoolbox.com/